A 25 g piece of characoal is found in some ruins of an ancient city. The sample shows a `C^(14)` activity of 250 decay/minutes. How long has the three this charcoal came from been dead ? Given, the half-life of `C^(14)` is 5730 years. The ratio of `C^(14) and C^(12)` in the living sample is 1.3 `xx 10^(-12)`.

Explanation

To solve the problem of determining how long the charcoal has been dead based on its Carbon-14 activity, we can follow these steps:

### Step-by-Step Solution:

1. **Identify Given Values:**
- Mass of charcoal (m) = 25 g
- Activity of the sample (A) = 250 decay/min
- Half-life of Carbon-14 (t_half) = 5730 years
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