Home
Class 12
PHYSICS
In "".(88)Ra^(226) nucleus there are...

In `""._(88)Ra^(226)` nucleus there are

A

138 protons and 88 neutrons

B

138 neutrons and 88 protons

C

226 neutrons and 88 electons

D

226 neutons and 138 electrons

Text Solution

Verified by Experts

The correct Answer is:
b

`""_(Z)X^(A)=""_(88)Ra^(226)`
Number of protons = Z = 2
Number of neutrons = A - Z = 2
Promotional Banner

Topper's Solved these Questions

  • NUCLEI

    DC PANDEY|Exercise checkpoint 13.2|15 Videos
  • NUCLEI

    DC PANDEY|Exercise CHECK POINT 13.3|15 Videos
  • NUCLEI

    DC PANDEY|Exercise C MADICAL ENTRANCES GALLERY|46 Videos
  • MODERN PHYSICS - 2

    DC PANDEY|Exercise Level 2 Subjective|10 Videos
  • RAY OPTICS

    DC PANDEY|Exercise Medical entrance gallary|76 Videos

Similar Questions

Explore conceptually related problems

In ._88Ra^(226) nucleus, there are.

The ._(88)^(226)Ra nucleus undergoes alpha -decay to ._(88)^(226)Rn . Calculate the amount of energy liberated in this decay. Take the mass of ._(88)^(226)Ra to be 226.025 402 u , that of ._(88)^(226)Rn to be 222.017 571 u , and that of ._(2)^(4)He to be 4.002 602 u .

When the radioactive isotope _(88)Ra^(226) decays in a series by emission of three aplha (alpha) and a beta (beta) particle, the isotope X which remains undecay is

An isotope ._(92)U^(238) decays successively to form ._(90)Th^(234),._(91)Pa^(234),._(90)Th^(234),._(90)Th^(230) and ._(88)Ra^(226) . What are the radiations emitted in these five steps?

When the radioactive isotope ._(88)Ra^(228) decays in series by the emission of 3 alpha and 1 beta particle, the isotope finally formed is

Uranium ores contain one radium -226 atom for every 2.8 xx 10^(6) uranium -238 atoms. Calculate the half-life of ._(88)Ra^(226) is 1600 years (._(88)Ra^(226) is a decay product of ._(92)U^(238)) .