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The radius of a nucleus of a mass number...

The radius of a nucleus of a mass number `A` is directly proportional to.

A

`A^(3)`

B

`A`

C

`A^(2//3)`

D

`A^(1//3)`

Text Solution

Verified by Experts

The correct Answer is:
d

Radius of nucleus, `R=R_(0)A^(1//3).` where, `R_(0)` is a constant and A is the mass number.
`R_(Cu)=(1.2xx10^(-15))(64)^(1//3)`
`=(1.2xx10^(-15))xx(4)^(1//3)`
`=4.8xx10^(-15)m=4.8fm`
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