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In a fission reaction .92^236 U rarr ^11...

In a fission reaction `._92^236 U rarr ^117 X + ^117Y + n + n`, the binding energy per nucleon of `X` and `Y` is `8.5 MeV` whereas of `.^236 U` is `7.6 MeV`. The total energy liberated will be about.

A

200 keV

B

2 MeV

C

200 MeV

D

2000 MeV

Text Solution

Verified by Experts

The correct Answer is:
C
Energy released = Products energy - Reactant energy
`=8.5xx234-7.6xx236`
`=1985.4Me V~~ 200 Me V`
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