In the reaction, identify`X,""_(7)N^(14)+alphato""_(8)X^(17)+""_(1)P^(1)`

Options

A. An oxygen nucleus with mass 17
B. An oxygen nucleus with mass 16
C. An nitrogen nucleus with mass 17
D. A nitrogen nucleus with mass 16

Answer

To solve the problem, we need to identify the nucleus represented by "X" in the nuclear reaction given:

\[ _{7}^{14}N + \alpha \rightarrow _{8}^{17}X + _{1}^{1}P \]

### Step-by-Step Solution:

1. **Identify the Components of the Reaction:**
- The reaction involves a nitrogen nucleus (N) with atomic number 7 and mass number 14.
- An alpha particle (α), which is represented as \(_{2}^{4}He\), is bombarding the nitrogen nucleus.
- The products of the reaction include a nucleus represented by "X" with an atomic number of 8 and mass number of 17, and a proton \(_{1}^{1}P\).

2. **Write the Reaction in Standard Form:**
- The reaction can be written as:
\[ _{7}^{14}N + _{2}^{4}He \rightarrow _{8}^{17}X + _{1}^{1}P \]

3. **Conservation of Mass Number and Atomic Number:**
- According to the conservation laws in nuclear reactions, the sum of the mass numbers and the sum of the atomic numbers must be equal on both sides of the equation.
- On the left side:
- Mass number: \(14 + 4 = 18\)
- Atomic number: \(7 + 2 = 9\)
- On the right side:
- Mass number: \(17 + 1 = 18\)
- Atomic number: \(8 + 1 = 9\)

4. **Determine the Identity of "X":**
- From the reaction, we see that the nucleus "X" has an atomic number of 8 and a mass number of 17.
- The element with atomic number 8 is oxygen (O).

5. **Final Answer:**
- Therefore, the nucleus represented by "X" is \(_{8}^{17}O\), which is an oxygen nucleus with a mass number of 17.

### Conclusion:
The value of "X" is \(_{8}^{17}O\) (Oxygen-17).

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