The half-life `(T)` and the disintegration constant `(lamda)` of a radioactive substance are related as

Options

A. `lamdaT _(1//2)`
B. `lamdaT_(1//2)= 0.693`
C. `(T_(1//2))/(lamda)=0.693`
D. `(lamda)/(T_(1//2))=0.693`

Answer

B

Explanation

We have, N= `N_(0)e^(-lamda)`
`(N_(0))/(2)=N_(0)e^(-lamdaT1//2)implies2=e^(lamdaT1//2)`
By taking log both the side,
log `2= lamdaT_(1//2)`
`lamdaT_(1//2)=0.693`