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The half-life of pononium is 140 days. A...

The half-life of pononium is `140` days. After how many days. `16 gm` polonium will be reduced to `1 gm` (or `15 gm` will decay) ?

A

700 days

B

280 days

C

560 days

D

420 days

Text Solution

Verified by Experts

The correct Answer is:
C
We have `(N)/(N_(0))=((1)/(2))^(t//140)[thereforeN=No((1)/(2))^(n)andt=nt_(1//2)]`
`1/16=((1)/(2))^(t//140)impliest/140=4(t_(1//2)=140days)`
`impliest=560 days`
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