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When the radioactive isotope (88)Ra^(226...

When the radioactive `isotope _(88)Ra^(226)` decays in a series by emission of three aplha `(alpha)` and a beta `(beta)` particle, the isotope X which remains undecay is

A

`83^(X)^(214)`

B

`84^(X)^(218)`

C

`84^(X)^(220)`

D

`87^(X)^(223)`

Text Solution

Verified by Experts

The correct Answer is:
A
Due to emission os `3alpha` particles, the mass number is reduced by 12 while atomic number is decresed by 6. Due to emission of `beta` particle the atomic number is increased by one while there is no change in mass number is decreased by 5. so isotope X is is `X^(214)`
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