Capacitor `C_(1)` of the capacitance `1muF` and another capacitor `C_(2)` of capacitance `2muF` are separately charged fully by a common battery.The two capacitors are then separately allowed to discharge through equal resistors at time `t=0`.

Options

A. the current in each of the two discharging circuits is zero at t=0
B. the currents in the two dischrging circuits at t=0 are equal but non-zero
C. the currents in the two discharging circuits at t=0
D. Capacitor `C_(1)` loses 40% of initial charge

Answer

b

Explanation

Here `,V_(0)` and r in the two CR circuits are same hence the currents in the two discharging circuits at `t=0(V_(0)//R)` will be same
we know that time constant of a resistance and capacitance circuit is CR .Here time constant of first circuit `(capacity C_(1)=1muf)`is half of the time constatn of second circuit `(capacity C_(2)=2muf) Hence C_(1)` losses 50% its intial charge sooner.