Home
Class 9
MATHS
Equilateral triangles ABD and ACE are dr...

Equilateral triangles ABD and ACE are drawn on sides AB and AC respectively of a `DeltaABC` outside it. Prove that :
(i) `angleDAC= angleEAB` (ii) `DC = BE`

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • TRIANGLES

    NAGEEN PRAKASHAN|Exercise Exercise 7b|15 Videos
  • TRIANGLES

    NAGEEN PRAKASHAN|Exercise Revision Exercise (very Short Answer Questions)|10 Videos
  • TRIANGLES

    NAGEEN PRAKASHAN|Exercise Problems From NCERT/exemplar|5 Videos
  • SURFACE AREA AND VOLUME

    NAGEEN PRAKASHAN|Exercise Revision Exercise (long Answer Questions)|10 Videos

Similar Questions

Explore conceptually related problems

The given figure showns a parallelogram ABCD. Squares ABPQ and ADRS are drawn on sides AB and AD respectively of the parallelogram ABCD. Prove that : (i) angleSAQ=angleABC (ii) SQ=AC

D and E are points on sides AB and AC respectively of Delta ABC such that ar( Delta DBC) = ar( Delta EBC). Prove that DE I I BC.

Two circles are drawn with sides AB and AC of a triangle ABC as diameters

In DeltaABC , BD and CE are perpendicluars to the sides AC and AB respectively and BD = CE. Prove that DeltaBCD~=DeltaCBE .

The square ABGH and ADEF are drawn on the sides AB and AD of a parallelogram ABCD. Prove (i) /_FAH=/_ABC, (ii) FH=AC .

P and Q are the points on sides AB and AC respectively of a DeltaABC , such that PQ||BC .If AP|PB=2:3 and AQ=4 cm , then the length of AC is ….. Cm .

ABC is an equilateral triangle,and AD and BE are perpendiculars to BC and AC respectively. Prove that: 1.AD=BE 2.BD =CE[Delta ABD=Delta BCE.]

ABC is a triangle in which altitude BE and CF drawn on AC and AB respectively are equal. Prove that DeltaBEC~=DeltaCFB

NAGEEN PRAKASHAN-TRIANGLES-Exercise 7a
  1. Given AD=DC and DB biscets angleADC. (i) Prove that, DeltaADB cong D...

    Text Solution

    |

  2. The adjoining figure shows a square ABCD and an equilateral triangle D...

    Text Solution

    |

  3. Equilateral triangles ABD and ACE are drawn on sides AB and AC respect...

    Text Solution

    |

  4. The following figure shows a square ABCD and an equilateral triangle D...

    Text Solution

    |

  5. The given figure showns a parallelogram ABCD. Squares ABPQ and ADRS ar...

    Text Solution

    |

  6. In a DeltaABC, BD is the median to the side Ac, BD is produced to E su...

    Text Solution

    |

  7. In the given figure, angleBDC=angleBEA and AB = BC. Show that AE=CD.

    Text Solution

    |

  8. If the diagonals of a quadrilateral bisect each other at right angle, ...

    Text Solution

    |

  9. In the adjoining figure, BM and DN are the perpendiculars from B and D...

    Text Solution

    |

  10. In the adjoining figure, AB=EF, BC=DE, angleABC=angleFED=90^(@), prove...

    Text Solution

    |

  11. In the adjoining figure, ABCD is a parallelogram. If angleMBC = angleN...

    Text Solution

    |

  12. In the adjoining figure, QX and RX are the bisectors of the angles Q a...

    Text Solution

    |

  13. In the following figure, OA = OC and AB = BC. Prove that : (i) angle...

    Text Solution

    |

  14. In the adjoining figure, ABCD is a paralogram. The side AB is produced...

    Text Solution

    |

  15. In the following figures, AB=PQ, AC=PR and AM=PN. Prove that DeltaABC ...

    Text Solution

    |

  16. Prove that the medians of an equilateral triangle are equal.

    Text Solution

    |

  17. ABCD is a square EF is parallel to BD. R is the mid-point of EF. Prove...

    Text Solution

    |

  18. The following figure shows a triangle ABC in which Ab = AC. M is a poi...

    Text Solution

    |

  19. In the given figure, AB"||"DC and angleD=angleC. Prove that : (i) AD...

    Text Solution

    |

  20. In the following figure, AB||FD, AC||GE and BD = CE. Prove that : (i...

    Text Solution

    |