The side AB of a parallelogram ABCD is produced to any point E. A line through A and parallel to CE meets CB produced at G and then parallelogram EBGF is completed (see the figure). Prove that
area of `||gm ABCD = " area of "||gm BEFG`.

The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q and then parallelogram PBQR is completed as shown in Figure. Show that ar(||^(gm) ABCD)=ar (||^(gm) PBQR)

The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q and then parallelogram PBQR is completed. Show that a r" "(A B C D)" "=" "a r" "(P B Q R)dot

The side A B of a parallelogram A B C D is produced to any point Pdot A line through A and parallel to C P meets C B produced at Q and then parallelogram P B Q R is completed as shown in Figure. Show that a r(^(gm)A B C D)=a r ^(gm)P B Q R)dot

The side A B of a parallelogram A B C D is produced to any point Pdot A line through A parallel to C P meets C B produced in Q and the parallelogram P B Q R completed. Show that a r(^(gm)A B C D)=a r(^(gm)B P R Q)dot CONSTRUCTION : Join A C and PQ. TO PROVE : a r(^(gm)A B C D)=a r(^(gm)B P R Q)

The side AD of parallelogram ABCD is produced to a point E. BE intersects CD at F. Show that Delta ABE~ Delta CFB .

The area of any parallelogram ABCD, is AB X BC.

The sides AB and CD of a parallelogram ABCD are bisected at E and F. Prove that EBFD is a parallelogram.

In the figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that ar( Delta AEDF) = ar( Delta ABCDE)

ABCD is a parallelogram.AB is produced to E so that BE=AB. Prove that ED bisects BC .