In the given figure, `BC||XY, BX||CA and AB ||YC`. Prove that area `(DeltaABX) = " area " (Delta ACY)`

In Figure,BC|XY,BX|CA and AB||YC Prove that: ar(ABX)=ar(ACY)

In the adjoining figure, DE || BC . Prove that area (Delta ACD) = " area " (Delta ABE)

In the adjoining figure, BD = DC and AE = ED. Prove that area of Delta ACE = (1)/(4) " area of " Delta ABC

In the adjoning figure, ABCD is a parallelogram. Prove that : area of Delta BPC = " area of " Delta DPQ

ABCD is a trapezium with AB||DC. A line parallel to AC intersects AB at X and BC at Y. Prove that ar( Delta ADX) = ar( Delta ACY).

In the given figure, MN||BC and AM: MB=1:2 Find ("area" (Delta AMN))/("area" (Delta ABC))

In the given figure, DE||BC . If DE=3 cm, BC=6 and ar (Delta ADE)=15 cm^(2) , find the area of Delta ABC .

In Delta ABC, D, E, F are respectively the mid points of the sides AB, BC and AC. Find ratio of the area of Delta DEF and area of Delta ABC .

In the given figure, DE||BC and DE:BC=3:5 . Calculate the ratio of areas of Delta ADE and the trpezium BCED.