A dice is thrown twice and the sum of numbers apear to be 6. Find the probability of getting 4 on at least one throw.

Answer

N/a

Explanation

In two throws of a dice, the sample space
`n(S)=36`
Let `E=` event of getting a sum of 6
`={(1,5),(2,4),(3,3),(4,2),(5,1)}`
and `F=` event of getting 4 on at least one throw
`={(4,1),(4,2),(4,3),(4,4),(4,5),`
`(4,6),(1,4),(2,4),(3,4),(5,4),(6,4)}`
`:. EnnF={(4,2),(2,4)}`
Now `P(F//E)=(P(FnnE))/(P(E))=(2//36)/(5//36)=2/5`