Arrive at an expression for pressure at point due to a liquid.

Explanation

Let .h. be the depth of point .p. let a liquid cylinder of base area and height "h. is resting on the point force exerted by liquid cylinder - mg where m- (Ahp)
`therefore W=(Ahrho)g`
By definition `P=W/A`
i.el, `P=(Ahrho theta)/(A)`
or `P=hrhog`
For a given liquid and for low depths (upto 10 km) Pah
Total pressure at a point inside `=P_(c)+P_(l)" where "P_(o)`= atmospheric pressure, `P_(t)`= liquid pressure.