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Four resistors of resistances 2Omega, 4O...

Four resistors of resistances `2Omega, 4Omega, 6Omega` and `2Omega` are connected in a cyclic order of a Wheatstone's network. What resistance should be connected with `2Omega` in the arm AD so as to balance the network?

Text Solution

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For a balanced network,
`P/Q=R/S`
i.e., `2/4=x/6`
i.e., `x=1/2xx6=3Omega`
Since `xgt2Omega`, a resistor of `.1Omega.` resistance is connected in series with `2Omega` in the arm AD to balance the network.
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