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In the given circuit, calculate the curr...

In the given circuit, calculate the current through `3Omega` resistor, when circuit is connected to `12V` battery.

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Hence Branch current in `3Omega=(IR_(2))/(R_(1)+R_(2))`
i.e., `I_(1)=(11.66xx1.565)/(3+1.565)=3.977` A
Branch current in `3Omega` resistor is 4.0 A
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