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Critical angle for light going from medi...

Critical angle for light going from medium (i) to (ii) is `theta` . The speed of light in medium (i) is v then speed in medium (ii) is

A

`v(1-costheta)`

B

`(v)/(sintheta)`

C

`v/(costheta)`

D

`v/((1-sintheta))`

Text Solution

Verified by Experts

The correct Answer is:
B
`sin theta = (mu_(2))/(mu_(1)) = (v)/(v_(1))` or `v' = (v)/(sintheta)`
where v and v' are the speeds to light in medium (i) and medium (ii) respectively.
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