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A ray of light is incident at 60^(@) on ...

A ray of light is incident at `60^(@)` on one face of a prism of angle `30^(@)` and the emergent ray makes `30^(@)` with the incident ray. The refractive index of the prism is

A

`1.732`

B

`1.414`

C

`1.5`

D

`1.33`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the refractive index of the prism given the angle of incidence, the angle of the prism, and the angle of deviation. Here’s a step-by-step solution: ### Step 1: Identify the given values - Angle of incidence (i) = 60° - Angle of prism (A) = 30° - Angle of deviation (D) = 30° (since the emergent ray makes an angle of 30° with the incident ray) ### Step 2: Use the formula relating the angles The formula that relates the angles in a prism is: \[ A + D = i + e \] Where: - A = angle of prism - D = angle of deviation - i = angle of incidence - e = angle of emergence ### Step 3: Substitute the known values into the formula Substituting the known values into the equation: \[ 30° + 30° = 60° + e \] This simplifies to: \[ 60° = 60° + e \] ### Step 4: Solve for the angle of emergence (e) From the equation: \[ e = 60° - 60° = 0° \] ### Step 5: Use the relation between the angles of refraction and the angle of prism We know that: \[ r_1 + r_2 = A \] Where: - \( r_1 \) = angle of refraction at the first face - \( r_2 \) = angle of refraction at the second face Since \( e = 0° \), it implies that \( r_2 = 0° \). Thus: \[ r_1 + 0° = 30° \] So, \( r_1 = 30° \). ### Step 6: Apply Snell's law at the first face Using Snell's law at the first face of the prism: \[ n = \frac{\sin(i)}{\sin(r_1)} \] Where \( n \) is the refractive index of the prism. Substituting the known values: \[ n = \frac{\sin(60°)}{\sin(30°)} \] ### Step 7: Calculate the sine values We know: - \( \sin(60°) = \frac{\sqrt{3}}{2} \) - \( \sin(30°) = \frac{1}{2} \) ### Step 8: Substitute the sine values into the equation Now substituting the sine values: \[ n = \frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}} \] This simplifies to: \[ n = \sqrt{3} \] ### Conclusion The refractive index of the prism is: \[ n \approx 1.732 \]

To solve the problem, we need to find the refractive index of the prism given the angle of incidence, the angle of the prism, and the angle of deviation. Here’s a step-by-step solution: ### Step 1: Identify the given values - Angle of incidence (i) = 60° - Angle of prism (A) = 30° - Angle of deviation (D) = 30° (since the emergent ray makes an angle of 30° with the incident ray) ### Step 2: Use the formula relating the angles ...
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