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If radius of earth contracted by 0.1% , ...

If radius of earth contracted by 0.1% , its mass remaining same then weight of the body at earth's surface will increase by

A

`0.1%`

B

`0.2%`

C

`0.3%`

D

Remains same

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AI Generated Solution

The correct Answer is:
To solve the problem of how the weight of a body at the Earth's surface will change if the radius of the Earth contracts by 0.1% while its mass remains the same, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Relationship**: The weight \( W \) of a body on the surface of the Earth is given by the formula: \[ W = mg \] where \( m \) is the mass of the body and \( g \) is the acceleration due to gravity at the surface of the Earth. 2. **Formula for Acceleration due to Gravity**: The acceleration due to gravity \( g \) can be expressed as: \[ g = \frac{GM}{R^2} \] where \( G \) is the universal gravitational constant, \( M \) is the mass of the Earth, and \( R \) is the radius of the Earth. 3. **Change in Radius**: If the radius of the Earth contracts by 0.1%, then the new radius \( R' \) can be calculated as: \[ R' = R - 0.001R = 0.999R \] 4. **New Acceleration due to Gravity**: Substitute \( R' \) into the formula for \( g \): \[ g' = \frac{GM}{(R')^2} = \frac{GM}{(0.999R)^2} = \frac{GM}{0.998001R^2} \] Thus, the new acceleration due to gravity \( g' \) becomes: \[ g' = \frac{g}{0.998001} \] 5. **Calculate the Change in Weight**: The new weight \( W' \) of the body is: \[ W' = mg' = m \left(\frac{g}{0.998001}\right) = \frac{mg}{0.998001} = \frac{W}{0.998001} \] 6. **Percentage Change in Weight**: To find the percentage change in weight, we can calculate: \[ \Delta W = W' - W = \left(\frac{W}{0.998001} - W\right) = W\left(\frac{1 - 0.998001}{0.998001}\right) = W\left(\frac{0.001001}{0.998001}\right) \] The percentage change in weight is: \[ \text{Percentage Change} = \left(\frac{\Delta W}{W}\right) \times 100 = \left(\frac{0.001001}{0.998001}\right) \times 100 \approx 0.1003\% \] 7. **Conclusion**: Therefore, the weight of the body at the Earth's surface will increase by approximately \( 0.1003\% \).
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