Home
Class 12
PHYSICS
An infinite thin plane sheet of charge d...

An infinite thin plane sheet of charge density `7.08 xx 10^(-11)(C //m^(2))` is held in air. Find the electric field at a point very close to the sheet.

Text Solution

Verified by Experts

`E=(sigma)/(2epsilon_(0))=(7.08xx10^(-11))/(2xx8.854xx10^(-12))=4` (N/C)
Promotional Banner

Similar Questions

Explore conceptually related problems

An infinite plane sheet of charge density 10^(-8) Cm^(-2) is held in air. In this situation how far apart are two equipotenitial surfaces, whose p.d is 5 V ?

Field Of An Infinite Plane Sheet Of Charge

Two parallel large thin metal sheets have equal surface charge densities (sigma = 26.4 xx 10^(-12) C//m^(2)) of opposite signs. The electric field between these sheets is

A plane conductor with very large dimensions is charged such that surface charge density is 1.6xx10^(-2)C//m^(2) . The electric field intensity at a point near it if the conductor is in a medium of dielectric constant 5 is

An infinitely large non-conducting sheet of thickness t and uniform volume charge density rho is given in which left half og the sheet contains charge density rho and right half contains charge density. Find the electric field at the symmetry plane of this sheet

The energy density at a point in vacuum is 1.77xx10^(-7)J//m^(3) . The intensity of the electric field at the point is

The surface density of charge on a conductor situated in air, is 2xx10^(-4)C//m^(2) . The electric intensity at a point very near to its surface is

There is an infinite non conducting sheet of charge having uniform charge density sigma . The electric field at a point P at a distance x from the sheet is E_(0) . Point O is the foot of the perpendicular drawn from point P on the sheet. A circular portio of radius r lt lt x centered at O is removed from the sheet. Now the field at point P becomes E_(0)-DeltaE . Find DeltaE .