If potential difference between the plates of capacitor changes with rate of `(dV)/(dt) = 10^(6) ("volt")/("sec")`, and capacitance of capacitors is `1 muF`, then find displacement current between the plates.

Explanation

`I_(d) = C xx (dV )/(dt)`
`-1. xx 10^(-6) xx 10^(6)`
`=1.0A`