The nuclei `""_6A^(13) and ""_7B^(14)` can be described as

Options

A. isotones
B. isobars
C. isotopes of carbon
D. isotopes of nitrogen

Answer

To describe the nuclei \( _6A^{13} \) and \( _7B^{14} \), we need to analyze their atomic numbers and mass numbers.

### Step 1: Identify the Atomic Number and Mass Number
- For nucleus \( _6A^{13} \):
- Atomic Number (Z) = 6
- Mass Number (A) = 13

- For nucleus \( _7B^{14} \):
- Atomic Number (Z) = 7
- Mass Number (A) = 14

### Step 2: Calculate the Number of Protons and Neutrons
- The atomic number (Z) represents the number of protons in the nucleus.
- The mass number (A) is the sum of the number of protons (Z) and the number of neutrons (N).

#### For nucleus \( _6A^{13} \):
- Number of Protons (P) = Atomic Number (Z) = 6
- Mass Number (A) = Number of Protons (P) + Number of Neutrons (N)
\[ 13 = 6 + N \]
\[ N = 13 - 6 = 7 \]
- Therefore, \( _6A^{13} \) has 6 protons and 7 neutrons.

#### For nucleus \( _7B^{14} \):
- Number of Protons (P) = Atomic Number (Z) = 7
- Mass Number (A) = Number of Protons (P) + Number of Neutrons (N)
\[ 14 = 7 + N \]
\[ N = 14 - 7 = 7 \]
- Therefore, \( _7B^{14} \) has 7 protons and 7 neutrons.

### Step 3: Conclusion
- The nuclei \( _6A^{13} \) and \( _7B^{14} \) can be described as follows:
- \( _6A^{13} \): 6 protons and 7 neutrons
- \( _7B^{14} \): 7 protons and 7 neutrons

### Summary
- \( _6A^{13} \) is a carbon isotope (since Z=6 corresponds to carbon) with 7 neutrons.
- \( _7B^{14} \) is a nitrogen isotope (since Z=7 corresponds to nitrogen) with 7 neutrons.