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When .90 Th^228 transforms to .83 Bi^212...

When `._90 Th^228` transforms to `._83 Bi^212`, then the number of the emitted `alpha-`and `beta-`particle is, respectively.

A

`4alpha,7beta`

B

`4alpha,1beta`

C

`8alpha,7beta`

D

`4beta,4alpha`

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The correct Answer is:
B
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