If the rate of a reaction gets doubled as the temperature is increased from `27^@ " to " 37^@C`. Find the activation energy of reaction?

Explanation

To find the activation energy (Ea) of the reaction given that the rate doubles when the temperature increases from 27°C to 37°C, we can use the Arrhenius equation and the concept of the rate constant.

### Step-by-Step Solution:

1. **Convert temperatures from Celsius to Kelvin**:
- \( T_1 = 27°C = 27 + 273 = 300 \, K \)
- \( T_2 = 37°C = 37 + 273 = 310 \, K \)

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