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For the hypothetical reaction 2A rarr3C...

For the hypothetical reaction `2A rarr3C` , the reaction rate r in terms of the rate of change of the concentration is given by

A

`r=-(d[A])/(dt)`

B

`r=-1/2(d[A])/(dt)`

C

`r=1/3(d[A])/(dt)`

D

`r=(d[A])/(dt)`

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The correct Answer is:
To derive the expression for the reaction rate \( R \) in terms of the rate of change of concentration for the hypothetical reaction \( 2A \rightarrow 3C \), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reaction**: The reaction given is \( 2A \rightarrow 3C \). Here, \( A \) is the reactant and \( C \) is the product. 2. **Define the Rate of Reaction**: The rate of reaction \( R \) can be expressed in terms of the change in concentration of the reactants and products over time. 3. **Express the Rate in Terms of Reactants**: For the reactant \( A \), since it is being consumed, the rate of disappearance can be expressed as: \[ R = -\frac{1}{2} \frac{d[A]}{dt} \] Here, the negative sign indicates that the concentration of \( A \) is decreasing, and the factor \( \frac{1}{2} \) comes from the stoichiometry of the reaction (2 moles of \( A \) are consumed). 4. **Express the Rate in Terms of Products**: For the product \( C \), since it is being formed, the rate of appearance can be expressed as: \[ R = \frac{1}{3} \frac{d[C]}{dt} \] Here, the positive sign indicates that the concentration of \( C \) is increasing, and the factor \( \frac{1}{3} \) comes from the stoichiometry of the reaction (3 moles of \( C \) are produced). 5. **Final Expression for Rate**: Thus, we can summarize the rate of reaction in terms of the concentrations of \( A \) and \( C \): \[ R = -\frac{1}{2} \frac{d[A]}{dt} = \frac{1}{3} \frac{d[C]}{dt} \] ### Conclusion: The rate of the reaction \( R \) can be expressed as: \[ R = -\frac{1}{2} \frac{d[A]}{dt} \] or \[ R = \frac{1}{3} \frac{d[C]}{dt} \]
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