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The rate law for a reaction between the ...

The rate law for a reaction between the substances A and B is given by
Rate = `k[A]^(n)[B]^(m)`
On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as:

A

`1/(2^(n+m))`

B

`m+n`

C

`2^(n+m)`

D

`2^(n-m)`

Text Solution

Verified by Experts

The correct Answer is:
C
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