If `p(x)=x^(2)-3x+2" then "p(1)+p(-1)-p(0)` is ..............

Answer

To solve the problem, we need to evaluate the expression \( p(1) + p(-1) - p(0) \) using the polynomial \( p(x) = x^2 - 3x + 2 \).

### Step-by-Step Solution:

1. **Calculate \( p(1) \)**:
\[ p(1) = 1^2 - 3 \cdot 1 + 2 \]
\[ = 1 - 3 + 2 \]
\[ = 0 \]

2. **Calculate \( p(-1) \)**:
\[ p(-1) = (-1)^2 - 3 \cdot (-1) + 2 \]
\[ = 1 + 3 + 2 \]
\[ = 6 \]

3. **Calculate \( p(0) \)**:
\[ p(0) = 0^2 - 3 \cdot 0 + 2 \]
\[ = 0 + 0 + 2 \]
\[ = 2 \]

4. **Combine the results**:
Now we substitute the values we calculated into the expression:
\[ p(1) + p(-1) - p(0) = 0 + 6 - 2 \]
\[ = 6 - 2 \]
\[ = 4 \]

Thus, the final answer is:
\[ \boxed{4} \]