If `x^(2)+mx-30=(x-5) (x+6)` then m is ........

Answer

To solve the equation \( x^2 + mx - 30 = (x - 5)(x + 6) \) and find the value of \( m \), we will follow these steps:

### Step 1: Expand the Right-Hand Side (RHS)
We start by expanding the expression on the right side of the equation:

\[ (x - 5)(x + 6) = x^2 + 6x - 5x - 30 \]

### Step 2: Simplify the RHS
Now, we simplify the expression we obtained:

\[ x^2 + 6x - 5x - 30 = x^2 + (6x - 5x) - 30 = x^2 + x - 30 \]

### Step 3: Set the Equation
Now we can set the left-hand side (LHS) equal to the simplified RHS:

\[ x^2 + mx - 30 = x^2 + x - 30 \]

### Step 4: Compare Coefficients
Next, we compare the coefficients of \( x \) from both sides of the equation. The coefficient of \( x \) on the LHS is \( m \) and on the RHS is \( 1 \):

\[ m = 1 \]

### Step 5: Conclusion
Thus, the value of \( m \) is:

\[ \boxed{1} \]

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