The graph of the linear equation x+2y =5 passes through the point (0,5). True or False ??

Answer

To determine if the graph of the linear equation \( x + 2y = 5 \) passes through the point \( (0, 5) \), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Equation**: The given equation is \( x + 2y = 5 \).

2. **Rewrite the Equation**: To check if the point \( (0, 5) \) lies on the graph of this equation, we can rewrite it in standard form:
\[ x + 2y - 5 = 0 \]

3. **Substitute the Point**: We need to substitute \( x = 0 \) and \( y = 5 \) into the equation to see if it holds true:
\[ 0 + 2(5) - 5 = 0 \]

4. **Calculate the Left Side**: Now, calculate the left side:
\[ 0 + 10 - 5 = 10 - 5 = 5 \]

5. **Compare with Right Side**: The left side equals 5, while the right side of the equation is 0:
\[ 5 \neq 0 \]

6. **Conclusion**: Since the left side does not equal the right side, the point \( (0, 5) \) does not satisfy the equation \( x + 2y = 5 \). Therefore, the statement that the graph of the linear equation passes through the point \( (0, 5) \) is **False**.

### Final Answer:
The statement is **False**.