Find the area of isosceles triangle whose non equal side are of 12cm having the corresponding altitude 7.5 cm.

Answer

To find the area of the isosceles triangle with the given dimensions, we can follow these steps:

### Step 1: Identify the base and height of the triangle
In this problem, we have an isosceles triangle where the non-equal side (base) BC is given as 12 cm, and the corresponding altitude (height) from the vertex A to the base BC is given as 7.5 cm.

### Step 2: Use the formula for the area of a triangle
The formula for the area \( A \) of a triangle is given by:
\[ A = \frac{1}{2} \times \text{base} \times \text{height} \]

### Step 3: Substitute the values into the formula
Here, the base \( BC = 12 \) cm and the height \( h = 7.5 \) cm. Substituting these values into the formula gives:
\[ A = \frac{1}{2} \times 12 \times 7.5 \]

### Step 4: Calculate the area
First, calculate \( \frac{1}{2} \times 12 \):
\[ \frac{1}{2} \times 12 = 6 \]
Now, multiply this result by the height:
\[ 6 \times 7.5 = 45 \]

### Step 5: State the final area
Thus, the area of the isosceles triangle is:
\[ A = 45 \, \text{cm}^2 \]