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If the error in the measurement of radiu...

If the error in the measurement of radius is 2%, then the error in the determination of volume of the pshere will be

A

`8%`

B

`2%`

C

`4%`

D

`6%`

Text Solution

Verified by Experts

The correct Answer is:
D
Volume of the sphere `=(4)/(3)pir^(3)`
`[% " Error "=(DeltaA)/(A)xx100%]`
`"Here % "=(DeltaV)/(V)xx100`
`=(3Deltar)/(r )xx100`
`=3xx(2%)=6%`
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