Two blocks of masses m and 2m are placed on a smooth horizontal surface as shown in the first case only a force `F_(1)` is applied from the left later only a force `F_(2)` is applied from the right if the force acting at the interface of the two blocks in the two case is same then `F_(1):F_(2` is

Options

A. `1:1`
B. `1:2`
C. `2:1`
D. `1:3`

Answer

c

Explanation

Case 1 : a = `(F )/( "Total mass ")`
`a_(1) = (lambda )/( 3m )`
`N_(1) = ma_(1) = (m lambda)/( 3m ) = (lambda)/( 3)`
Case 3
`a_(2) = (lambda )/(3m)`
`N_(1) = N_(2)`
`(f_(1))/( f_(2)) = (2)/(1)`