Calculate the moment of inertia of a cylinder of length `1.5m`, radius 0.05m and density `8xx10^(3)kgm^(-3)` about the axis of the cylinder.

Explanation

Here `R=0.05m, l=1.5m`
`rho=8xx10^(3)kgm^(-3)`
Mass of cylinder
M = Volume `xx` density
`=pi R^(2)l.rho`
`=3.14xx(0.05)^(2)xx1.5xx8xx10^(3)`
`=94.2 kg`
M.I of the cylinder about its own axis,
`I=1/2 MR^(2)`
`=1/2xx94.2xx(0.05)^(2)`
`=0.1175kgm^(2)`