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The power out put of an automobile engin...

The power out put of an automobile engine is advertised to be 200 ap at 6000rpm. What is the corresponding torque?

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`P=200 hp=200hpxx(746omega)/(1hp)`
`=1.46xx10^(5)omega`
Angular velocity `omega=6000` rev/min
`=6000xx(2pi)/60=100xx2xx3.14`
`=628` rad/sec
Torque `tau=(rho)/(omega)=(1.49xx10^(5))/628`
`=237.5` Nm
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