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A particle moves in a circular path with...

A particle moves in a circular path with decreasing speed. What happens to its angular momentum?

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The angular momentum of a particle of mass m moving along a circular path of radius r with linear vellcity `vecv` is given by:
`vecL=vecrxxmvecv`
If the speed (v) of the particle decreases along the circular path, the magnitude of angular momentum `(=mvr)` decreases. However, the direction of angular momentum remains unchanged.
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