Three blocks of uniform thickness and masses m,m and 2m placed at three corners of a triangle having co-ordinates (2.5,1.5),(3.5,1.5) and (3,3) respectively.
Find the centre of mass of the system.

Explanation

Centre of mass of the system is given by
`x_(CM)=(m(2.5)+m(3.5)+2m(3))/(m+m+2m)`
`=2`
`y_(CM)=(m(1.5)+m(1.5)+2m(3))/(m+m+2m)`
`=2.25`