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A torque of 2.0xx10^(-4)Nm is applied to...

A torque of `2.0xx10^(-4)Nm` is applied to produce an angular acceleration of `4"rad"s^(-2)` in a rotating body. What is the moment of inertia of the body?

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Here `tau=2.0xx10^(-4)Nm`
`alpha=4"rad"s^(-2),I=?`
Formula `=tau=I alpha`
Moment of inertia
`I=(tau)/(alpha)=(2.0xx10^(-4))/4`
`=0.5xx10^(-4)kgm^(2)`
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