A particle performing uniform circular motion has angular momentum L. What will be the new angular momentum, if its angular frequencey is doubled and its kinetic energy halved?

Explanation

Rotatiional K.E.,
`K=1/2 Iomega^(2):l. I=(2K)/(omega^(2))`
Angular momentum,
`L=I omega=(2K)/(omega^(2)), omega=(2K)/(omega)`
When angular frequency is doubled and kinetic energy is halved, the angular momentum becomes,
`L'=(2(K/2))/(2omega)=1/4 . (2K)/(omega)=L/4`