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If the internal energy of an ideal gas U...

If the internal energy of an ideal gas U and volume V are doubled, then the pressure of the gas :

A

doubles

B

remains same

C

halves

D

quadruples

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaQ=DeltaU+DeltaW`
`DeltaU=DeltaU=DeltaQ-DeltaW`
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