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A gaseous mixture consists of 16g...

A gaseous mixture consists of 16g of helium and 16g of oxygen the ratio of two specific heats of the mixture is

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Number of moles `n_1=16/4=4, n_2=16/32=1/2`
For, He `C_V=3/2R,` For oxygen , `C_V=5/2R`
`C_(V)("mixture")=(4xx3/2R+1/2xx5/2R)/(4+1/2)=29/18R`
`gamma("mixture")=1+R/(C_V(mix))=1+R/(29//18R)`
`=1+18/29=47/29=1.62`
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