Calculate the root mean square speed of smoking practices of mass `5xx10^(-17)` kg in their Brownian motion in air at S.T.P

Explanation

Given `k = 1.38xx10^(-23) ` J/K
Here, `m = 5 xx10^(-17) kg, k = 1.38xx10^(-23)J//K`
`T = 0^@C=(0+273)K=273K,v_(rms)=? `
`v_(rms)=sqrt((3RT)/M)=sqrt((3kNT)/(mN))`
`=sqrt((3kT)/m)`
`sqrt((3xx1.38xx10^(-23)xx273)/(5xx10^(-17)))`
`v_(rms)=1.5xx10^(-2)m//s=1.5cm//s`