A vessel contains one mole of `O_2` gas (molar mass 32) at a temperature T. The pressure of the gas 1s.What will be the pressure of one mole of He (molar mass 4) at a temperature 2t in an identical vessel?

Explanation

Pressure of oxygen at temperature T is
Let the pressure of Helium be `P_("He")` at a temperature 2 T
Number of molecules of Helium
`n_("oxy")=32/16=2`
Number of molecules of Oxygen
`n_(He) = 4/2=2`
It is given that `(V_("OXY"))/(V_("He)) = 1`
From standard gas equation
`P=(nRT)/V`
We get , `P_("He")/(P_("OXY"))=(n_(He))/(n_("OXY"))xxT_(He)/(T_("OXY"))xxV_("OXY")/(V_(He))`
`P_("He")/(P_("OXY"))=2/2xx(2T)/Txx1`
`:. (P_(He))/(P_("OXY"))=2`
`:.` Pressure of 1 mole of Helium
=2 `xx` Pressure of 1 mole of oxygen