A pendulum is hung in a very high building and is moving freely to and fro like a simple harmonic oscillator. If the acceleration of the bob is `16 ms^(-1)` at a distance of 4 m from the mean position, then the time period is

Options

A. 2s
B. 1 s
C. `2pi s`
D. `pi s`

Answer

D

Explanation

`a= 16 m//s^(2), y=4`
`a-(g)/(l)x=- omega^(2) x`
`:. omega^(2)=(16)/(4)=4`
` omega=2`
Time period `T=(2pi)/(omega)=pis`