A uniform wire of length 20 m and weighing 5 kg hangs vertiacally . If `g=10 m//s^(2)`, then the speed of transverse wave is the middle of the wire :

Options

A. 4 m/s
B. `10 sqrt(2) m//s`
C. 0
D. `10 m//s`

Answer

D

Explanation

Here `mu=(5)/(20) kg//m=(1)/(4) kg//m`
`{:("Tension in the"),("middle of wire"):}}={{:("weight of half"),("middle of wire"):}`
`T=(5)/(2)g=(5)/(2)xx10 N=25 N`
As `v= sqrt((T)/(mu))`
`:.v=sqrt((25)/(1//4))=10 m//s`