Amplitude of a harmonic oscillator is A, when velocity of particle is half of maximum velocity, then determine position of particle.
The amplitude of a simple harmonic oscillator is doubled, how does this affect maximum velocity of the oscillator.
The amplitude of a simiple harmonic oscillator is tripled. How does this affect (i) the maximum velocity (ii) the total energy and (iii) the period of the oscillator?
The P.E. of a linear harmonic oscillator is 4J, when its displacment is equal to half its amplitude. The total energy of the particle is
A particle executes simple harmonic motion with an amplitude of 4cm At the mean position the velocity of tge particle is 10 earth distance of the particle from the mean position when its speed 5 point is
The amplitude of a simple harmonic oscillation is doubled. How does this affect (i) periodic time (ii) maximum velocity (iii) maximum acceleration and (iv) maximum energy
The velocity of a particle executing simple harmonic motion is
A particle is executing SHM of amplitude 10 cm. Its time period of oscillation is pi seconds. The velocity of the particle when it is 2 cm from extreme position is
A particle executes simple harmonic motion with an amplitude of 4 cm . At the mean position the velocity of the particle is 10 cm/ s . The distance of the particle from the mean position when its speed becomes 5 cm/s is
If amplitude of velocity is V_0 then the velocity of simple harmonic oscillator at half of the amplitude is