The potential energy of particle of mass 1kg moving along the x-axis is given by U(x) = 16(x^(2) - 2x) J, where x is in meter. Its speed at x=1 m is 2 m//s . Then,
The potential energy of a particle of mass 1 kg in motin along the x-axis is given by U = 4(1-cos2x)J Here, x is in meter. The period of small osciallationis (in second) is
The potential energy of a particle of mass 1kg in motion along the x- axis is given by: U = 4(1 - cos 2x) , where x in metres. The period of small oscillation (in sec) is
The potential energy of a particle of mass 2 kg moving along the x-axis is given by U(x) = 4x^2 - 2x^3 ( where U is in joules and x is in meters). The kinetic energy of the particle is maximum at
The potential energy of a particle of mass 5 kg moving in the x-y plane is given by U=(-7x+24y)J , where x and y are given in metre. If the particle starts from rest, from the origin, then the speed of the particle at t=2 s is
The potential energy of a particle of mass 1 kg moving in X-Y plane is given by U=(12x+5y) joules, where x an y are in meters. If the particle is initially at rest at origin, then select incorrect alternative :-
The potential energy of body of mass 2 kg moving along the x-axis is given by U = 4x^2 , where x is in metre. Then the time period of body (in second) is
The potential energy of a particle moving along x-axis is given by U = 20 + 5 sin (4 pi x) , where U is in J and x is in metre under the action of conservative force :
The potential energy of a particle of mass 1 kg moving along x-axis given by U(x)=[(x^(2))/(2)-x]J . If total mechanical speed (in m/s):-
