A `100g` block is connected to a horizontal massless spring of force constant `25.6 N//m`. The block is free to oscillate on a horizontal fricationless surface. The block is displced by `3 cm` from the equilibrium position, and at `t = 0`, it si released from rest at `x = 0`, The position-time graph of motion of the block is shown in figure.
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When the block is at position `A` on the graph, its
A `100g` block is connected to a horizontal massless spring of force constant `25.6 N//m`. The block is free to oscillate on a horizontal fricationless surface. The block is displced by `3 cm` from the equilibrium position, and at `t = 0`, it si released from rest at `x = 0`, The position-time graph of motion of the block is shown in figure.
When the block is at position `A` on the graph, its
When the block is at position `A` on the graph, its
A
position and velocity both are negative
B
position and velocity both are positive.
C
position is negative and velocity is positive.
D
position is positive and velocity is negative.
Text Solution
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The correct Answer is:
C
At position A, x is negative and `(dx)/(dt) ` is negative.
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A 100g block is connected to a horizontal massless spring of force constant 25.6 N//m . The block is free to oscillate on a horizontal fricationless surface. The block is displced by 3 cm from the equilibrium position, and at t = 0 , it si released from rest at x = 0 , The position-time graph of motion of the block is shown in figure. Let us now make a slight change to the initial conditions. At t = 0 , let the block be released from the same position with an initial velocity v_(1) = 64 cm//s . Position of the block as a function of time can be expressed as
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