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X(1) and X(2) are two points on the path...

`X_(1)` and `X_(2)` are two points on the path of a particle executing `SHM` in a straight line, at which its velocity is zero. Starting from a certain point `X(X_(1)XltX_(2)X)` then particle crosses this point again at successive intervals of `2s` and `4s` with a speed of `5m//s`.
The time period of `SHM` is

A

`6s`

B

`3s`

C

`4s`

D

`2s`

Text Solution

Verified by Experts

The correct Answer is:
A
Time period ` = 2 + 4 = 6s`
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