The speed (v) of particle moving along a straight line, when it is of a distance (x) from a fixed point on the line, is given by : `v^(2) = 144 - 9x^(2)`
Text Solution
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The correct Answer is:
(A) P, (B) S, (C) Q, (D) R
For (A) : `v^(2) = 144 - 9x^(2) rArr 2v (dv)/(dx) = 0 - 18x rArr a = -9x rArr omega^(2) =9 rArr omega = 3` Time period `T = (2pi)/(omega) = (2pi)/(3)` units For (B) `:' v^(2) ge 0 :. 144 - 9x^(2) ge 0 rArr x^(2) le 16 rArr x le 4 rArr "Amplitude" = 4 "units"` For (C) : Maximum velocity `= Aomega = (4)(3) = 12` units For (D) : At `x = 3` units, `a = -9x = - 27` units
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