Two particles execute SHM of same amplitude and frequency on parallel lines. They pass one another when moving in opposite directions each time their displacement is one third their amplitude. What is the phase difference between them?

Options

A. `30^(@)`
B. `60^(@)`
C. `90^(@)`
D. `120^(@)`

Answer

D

Explanation

`x = sin omegat = A/2 rArr omegat = pi/6` or `(5pi)/(6)`
Phse difference `= (5pi)/(6) - (pi)/(6) = (2pi)/(3)` or `120^(@)`
or

from phaser
`cos theta = (A//2)/(A) = 1/2 rArr theta = 60^(@)`
phase difference `2theta = 120^(@)`